Algebraic expressions.Elementary and Intermediate Algebra Essay

Algebraic expressionsIntroduction In the introduction to Algebra, the first assignment for the first week will involve using real numbers in place of integers to simplify expressions. Everyone needs to take his/her time to grasp the rules and the steps which are followed in algebra as this will form a concrete bow for the algebraic expression understanding. One needs to understand the mathematical fundamental elements so as not to incur problems in solving any algebraic problems. For instance, one needs to be clear with the properties of integers as these are the same properties which apply to the real numbers. The first step in dealing with equations is removing the parenthesis. If an equation requires you suppress the parenthesis from the equation, distribution becomes a necessity. Like terms should be grouped together when multiplying the integers that are inside the parenthesis to perform any indicated operation (Dugopolski, M.(2012), 2, p.67). The undermentioned is how I att empted to handle the assigned equations in the simplest form. In the left side of the page, I have put the mathematic equation, and in the right side at that place is my explanation of the steps I followed.2a(a-5)+4(a-5) Equation=2a-10a+4a-20 remove the permeative properties from the parenthesis= 2a -6a-20 then we get the coefficient.=a- 3a 10 then we simplify the expression.In the nigh equation,2.2w-3+3(w-4)-5(w-6) the equation=2w-3+3w-12-5w+30 remove the distributive properties from the parenthesis=2w+3w-5w-3-12+30 then we get the coefficients and.=15 combine themIn the third equation,3. 0.05(0.3m+35n)-0.8(-0.09n-22m) the equation=0.015m+1.75n+0.072n+17.6m remove the distributive property from the parenthesis=0.015m+17.6m+1.75n+0.072n simplify by putting the like terms together and=17.615m+1.822n combine themReferencesDugopolski, M. (2012). Elementary and Intermediate Algebra. New York, NY McGraw-Hill.Source document